(2x+3y)(x^2-3y)=

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Solution for (2x+3y)(x^2-3y)= equation:


Simplifying
(2x + 3y)(x2 + -3y) = 0

Multiply (2x + 3y) * (x2 + -3y)
(2x * (x2 + -3y) + 3y * (x2 + -3y)) = 0
((x2 * 2x + -3y * 2x) + 3y * (x2 + -3y)) = 0

Reorder the terms:
((-6xy + 2x3) + 3y * (x2 + -3y)) = 0
((-6xy + 2x3) + 3y * (x2 + -3y)) = 0
(-6xy + 2x3 + (x2 * 3y + -3y * 3y)) = 0
(-6xy + 2x3 + (3x2y + -9y2)) = 0

Reorder the terms:
(-6xy + 3x2y + 2x3 + -9y2) = 0
(-6xy + 3x2y + 2x3 + -9y2) = 0

Solving
-6xy + 3x2y + 2x3 + -9y2 = 0

Solving for variable 'x'.

The solution to this equation could not be determined.

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